Advanced Techniques のバックアップ(No.2)

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- 1 (2013-02-11 (月) 00:12:45)
- 2 (2013-02-11 (月) 01:14:09)

IF statement

a(T):rsrrsr
b(T):a(2-T)b(T-5)
c(T):b(T)sc(T-1)
c(20)

In this code, b(T) equals "rsrrsr" if T≡1 mod 5, and no moves otherwise.

f(T):sf(T-4)rf(T+7)
f(8)

This code realizes the loop

a:ssrsssrsssrsssr
a

In this loop, the number of "s" equals 4 + 7, and the number of "r" equals 7.
In generally, the code

f(T):[1]f(T-A)[2]f(T+B)

implies a loop with (A+B) times of "[1]" and B times of "[2]".

a(T):sa(T-37)ra(T+83)
a(1)

Since 83/37 approximately equals 9/4, this code is similar to

a(T):sa(T-4)ra(T+9)
a(1)

but the small difference changes the direction of the movement.
Therefore, "square minus square" shape can be drawn by a 12B code.

係数が1じゃないやつ

f(T):sf(T-4)rf(T-7)
f(255)

Probably, no problems in HOJ requires this method (even for "best solution") at this moment.

a(X):XXXXrXXXXla(srslX)
a(r)
(20B)

The code above can be compressed by replacing XXXX by another variable.

a(X,Y):YrYla(srslX,XXXX)
a(r,)
(19B)

Zとか？

f(X):ssXlssf(sX)
f()
(12B)

This code can be compressed by recycling "ss"：

f(X):ssXlf(f(sX))
f()
(11B)

育たない再帰とかで